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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O8 p% v* \ Q% o. C
6 j! {3 j: r+ y% {1 N) u& Q J
发现了一个有趣的现象，# G* X6 K6 [& [1 C: f7 N: P
每一条大路，
" k0 s# s' V# Q1 V( k按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f% K" G4 s$ n& J. p- H" b
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
5 C- W ^) g7 I( x6 M: O2 U) S按4珠路排列，有4种不同的路数/ i: J. K$ M1 w
按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
, j y& Z3 r/ R" ]" `什么意思呢，可能大家一时不清楚，& m! D! t9 {% x$ A* y( z6 ?
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l7 _5 Z8 ?) P* q
假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u4 H( Q8 ?0 v* ]* q/ g
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
' |1 z9 o$ x: @8 ?9 o w: T }够极端了吧
. |) I" R! j& F A+ A$ {6 Q按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F" c4 Q' |% v/ w/ r8 c
如果我们去掉第一口，就会出现完全相反的结果：- x; d3 j& |6 D! Y5 F9 c
21212121212121212121212121212121
- g: B& W2 [; H4 N/ N" A+ k Q变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
# j4 p! B" P& q* N* z) \3 V如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
: S' X3 C0 c( ?/ e! {! V所以每一条大路，! R6 V# q$ h. c; z% O
7 f# i1 w0 e! r: F1 H按2珠路排列，有2种不同的路数。# A4 |4 Y/ X3 V/ ]1 Z
再举一个列子：
2 T. ]7 ~8 t/ U; r4 u大路：122122122122122122。。。% x0 M& a7 y: U: k9 W
按三珠路排列：- J" |4 K% d( d" Z) J5 I6 E
122，122，122，122，122，122。。。
: M4 }/ {3 N( n" H去掉第一口，变成：6 G2 V! \" L' c" k: d
9 g% q2 H$ _5 ^! V221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
) s% z) N2 c$ H& D" B, h4 n4 M去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W
7 J1 d: ?2 y, M! j# s4 C212，212，212，212，212，: y& l, B; I6 e- m. J# c) `) G/ Q v: a9 F% F
去掉3口，又返回122，122，122，了$ {( }' @) D% \- o2 y7 t5 m8 h5 _
所以每一条大路，
# K! C2 ?' X* c, R, ]按3珠路排列，有3种不同的路数。5 L4 c. _* Z( ?
同理：按N珠路排列，有N种不同的路数。
1 Q" K, S6 L9 m, b8 ~我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O j9 }6 J' X: m# S+ {
字串83 L: R) G1 V- s2 Y+ Y
) s: W$ |+ c/ I- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
: }: k. Z9 y# l- O0 f. h1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |+ X( ~1 e3 F- s8 f# y
2、为三多理论提供了下注的多面性奠定基础。
! s8 t; c) y; q& ^. V( `" H, Z3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.; [8 ~# M" z+ R: c
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