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[打法交流] 百家乐珠路理论技巧(转)
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通过我几个月来对珠路理论的研究,5 R+ y* d$ ?  k6 I7 G/ O
2 p9 Q7 p: w# Q9 R% p) ~! X( c: A* J; P: `
发现了一个有趣的现象,/ B3 Y) O! [8 `8 N
每一条大路,, v2 R+ E5 x8 W2 Q5 Y2 D9 P. ?
按2珠路排列,有2种不同的路数1 _% l2 j  Y8 @" u) {# f, m- X5 G3 a! I
按3主路排列,有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z( f4 ?* E7 s& l2 T  B: c) Q( \1 v
按4珠路排列,有4种不同的路数
3 d! v; [( f/ [7 Q% e( v按N珠路排列,有N种不同的路数。: n1 f3 R9 @  p% ]* C
4 E# p  @9 D  A: f3 O什么意思呢,可能大家一时不清楚,
! o$ z( L; O1 j/ M) J我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 f# f3 c1 ~2 l
: s# {+ e9 x9 ?+ P8 Z假设大路开这样的路:! z  ~0 G3 v. K' o5 A4 ]" }5 w# u/ A8 ^5 Y5 ~5 ~9 a
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h  y7 r9 i6 y  [" x
够极端了吧
! ^; g* l# y& i/ j2 D按2珠路,就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
( F# [* h) z* @6 {! P; d如果我们去掉第一口,就会出现完全相反的结果:
3 k' E9 I! W7 E1 G21212121212121212121212121212121
' e4 ^( {* D6 f9 w变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C, O% h+ T# D2 c) n* S  a# J2 R
如果我们再去掉一口,又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
1 d( N+ M; ?: B所以每一条大路,! R6 V# q$ h. c; z% O
2 T5 S3 X: n" g" u, P/ f, u按2珠路排列,有2种不同的路数。6 n5 `3 z+ K0 {: L( [. _
再举一个列子:
0 N! e+ V2 d: ^; {' ?0 G大路:122122122122122122。。。
- D5 d' G3 q, V5 O( m  k& p$ G按三珠路排列:
1 h7 ~5 _! h) q0 x6 h122,122,122,122,122,122。。。6 L' d( y; _, r) x
去掉第一口,变成:6 G2 V! \" L' c" k: d
5 _4 [! U/ f& Q( e# Z221,221,221,221,221,+ R$ P2 d/ f7 Z, P5 M# X0 r8 Z* Q, n) ]; W/ @1 K. C
去掉前2口,变成:3 v1 q) z( ?2 f! }) U/ W5 X3 c& s$ E0 m3 [
212,212,212,212,212,: y& l, B; I6 e- m. J# c) `* s3 ?$ [. x' \. A1 l/ Y
去掉3口,又返回122,122,122,了$ Z# i& \6 q& Q% @1 v0 `! V
所以每一条大路,2 ?( w' d) H) `) F. w; }
按3珠路排列,有3种不同的路数。
4 a3 s# A  g# o$ [' ]; C同理:按N珠路排列,有N种不同的路数。
7 b" S6 S' J$ _/ Q我提出这个的意义在于:" v) X/ h3 }* D1 {5 J! a1 s. O
5 W$ t/ i  B; t3 b8 A3 J字串83 L: R) G1 V- s2 Y+ Y
; \/ {- o6 ~: u; ~( {$ j- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
2 p4 B3 n0 z# {1 G3 A0 O2 c$ a  }1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
! D; S, e* i4 i) D! p2、为三多理论提供了下注的多面性奠定基础。6 K6 _, q8 O( @7 b6 I, E# F
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.
, N, c+ q# `5 ?3 J

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