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[lastpost] => 2765450 【星宝】9月14日投注流水818元 1758338598 舞出精彩
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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。: J j1 \3 ]% P9 L* w' k; @+ ]
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假设大路开这样的路:) f3 H8 m' r! H: a0 v
p/ p2 l- Z# V. ^) H. P1 I9 F
12121212121212121212121212121212。
3 a: K5 l- T. L5 ?# d0 K) T; R3 l; n4 w3 Y$ X
按2珠路,就是BPBPBPBPBP。
) r# @& w0 p- z+ I5 j- _( [9 N7 f9 B7 X7 n
如果我们去掉第一口,就会出现完全相反的结果:8 F0 c3 t( ~) D" Y- f
" U% r9 B' R. x$ S; @
21212121212121212121212121212121。
9 Z% E9 p. o8 M7 F/ r" L2 @) I2 v3 E J
变成了PBPBPBPBPB。0 F; i2 M+ C {6 z9 P- }% c) z% d o
3 K6 D* \% K+ G- |/ E; k6 ~7 b* \
如果我们再去掉一口,又返回第一种情况了。3 b0 G& I: I0 B( J! @ n/ R i$ @6 b
4 t G" b# g( ~" B" O: P* d 所以每一条大路,按2珠路排列,有2种不同的路数。0 {# V/ V0 ]! S5 U5 `# H
* z) x+ N- _) o* k9 e, ^ 再举一个列子:4 O4 m) c2 t2 A: G
4 n! o7 D* I* ]; a 大路:122122122122122122。
0 |+ j2 Z2 Z u' W9 S( }" p! f9 }. T; X7 V- K* Z$ [
按三珠路排列:
]. L- }* B) _4 n% n: }: n$ O% o! A4 ~* v j& |
122,122,122,122,122,122。
9 O+ L- W4 h+ u9 J' M4 N6 f& M( I
8 @* p& o# q" w6 G 去掉第一口,变成:1 F; p- e% E" z4 \0 }- A
8 F4 J5 X0 V% M( H 221,221,221,221,221,去掉前2口,变成:
8 D2 e/ |$ N9 y& R; C _
$ K4 L# a$ L3 t: N6 F/ m 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
4 E' ]3 ^" d# l$ @! V0 y
1 }* F G* q" e: n& p P 同理:按N珠路排列,有N种不同的路数。
6 k) k0 W- B( X6 F! P0 E3 C% K* Y8 p( J% `; y8 E. M
我提出这个的意义在于:
. e# x j4 c) ?' y5 N) w
6 N0 X* v7 c8 a+ @ }( q 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。: I% ?2 s, x/ |* R% P- j
9 f1 u3 g6 P* D
2、为三多理论提供了下注的多面性奠定基础。& j# U6 i6 R: q
& d3 c6 F6 `9 Z/ X
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。9 N4 C2 V% u9 o
5 C, ]# d9 u9 e* t; S# G% z |
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我现在还是研究一下理论打法,感谢你的分享,我也来学习 |
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