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眼里没有庄闲,只有连和跳,因为庄闲是一对一的,而连跳都是一对二的。理解也好不理解也好,这个讲起来费劲,就不过多讲解了,你只要记住百家le只有连跳没有庄闲就可以了,通常大家所看见的大路,第一行是满的,从第二行开始才有洞出现。
0 ]1 i, O( v6 D0 A4 y
b+ c* v# ~6 E2 |3 o 用什么办法把第二行也变满,让洞出现到第三行去呢?这就需要重新排列大路。一种全新的方式去排列大路(又是新用什么排列,用连,和,跳连就可以比如大路是(随机的)7 B$ N, V9 H6 T7 o+ P
+ l5 r- v& u$ r; S+ i
第一行:OXOXOXOXOXOXOXOXOXOXOXOXOX(第一行永远是单跳)8 W) t1 q; ?0 B/ Q9 r
8 A' K$ ^1 o8 D3 t. T$ }& y 第二行:O X X O O OX O X (第二行开始出现洞)
5 `% s& I9 q# V1 r' V- y( `5 j. d" o$ R
第三行:O X O X X) }# Y3 k: [. R3 t
2 x' {; ~4 n! w' Z3 y2 f1 u
第四行:O X X
6 j8 n' [3 Z1 C/ k9 n) Z; P
/ S Z8 `) e% A/ P+ ~ O0 f 第五行: X
! b: |2 |% Q0 D" W/ A8 z/ M+ H& Z, a0 h4 N, J/ t
那么新写出来的大路是怎么样的呢?2 r, c# [8 |. u4 X
, b+ K% M, Z* D4 }9 {! h
记住一个简单的口诀就可以写出新的大路:1.连是连;2.跳连也是连。2 j s: t, ^1 E4 s4 E
/ \3 T5 t: X$ s1 P1 e7 V) Y+ D
如下(大家凑合着看吧,实在不行就自己拿笔抄一遍,和上面的路一一对应。)4 G, R( |% B+ S
- O1 U; }5 R) V" K& |: \! ]6 T 第一行:OXXOXOXO OXOOX(第一行不再是单跳了)# w' P5 F) Y, b- j, b; g0 {
& p& Z# M) R, H# U" |) [& O @+ ? 第二行:OOXXXOOX XXXXX (第二行也是全满的)
: X' L/ R: |) Z, c3 E: _3 x6 l7 [* K6 Z" s# D4 ~: b `
第三行:OX OX XO XOOX (第三行才出现洞)6 I$ F) {4 ~% b: f/ m, y
0 J3 b& U q5 O: j: \ 第四行:O XO O XXX
0 B* n3 e( Y9 r* h+ }6 @* G8 V( W/ Y7 o1 g
第五行: O
: G4 b' P2 Q$ A& v; N
: o d6 `7 k5 j+ d- E9 | 通过以上排列,大家看见了,变换了组合方式以后,大路不再显的那么杂乱无章了。每一列要么是连,要么就是跳连。这就似乎是最初期的关系形态变化组合排列,通过这样的排列,从形态上看,整个路只有12个形态上的跳,其他全是连贯的(可能已经有人开窍了)。' g# _' s# |2 ]- y# J/ k
+ F5 c. E. {' A% `2 E9 | 大家看第一行不再是完全的单跳,第二行没有洞的出现,第三行才开始出现洞,每一列最少是2个符号,通过这样的形态组合,实际上是减少了原本大路上的跳40%-60%,比如原来一靴牌60把,基本上是30个跳。30个左右连,而且是间隔无规律,杂乱无章的,按常规跳连的次数是基本一致的,周期越大,数字越接近。& v1 ` k O5 Z9 j+ H; m" p% ~
7 K# I7 U& f; J* W 通过配列 可以把原本大路的跳精简到10-15个左右,相反增加了40-60%的连,以上是对大路形态转换的最初级形态,相信已经能对大家有帮助。至于怎么样去下单 ,一目了然了。
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