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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。0 d. K6 z" q5 ~& \# {3 ?
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一般来说,. E0 m; g: G& f) r" E1 z
" y& V. P" a1 {9 a. f) n( r' l二连赢的概率是25%
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三连赢的概率是12.5%! z, }3 v( U5 _) U1 K
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四连赢的概率是6.25%3 `& ~& J9 `9 R( Z/ ~+ b: R @. l
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十连赢的概率是0.09765625%' ~9 m; S& p! W2 v7 E/ Y1 t% k7 e! f
5 {, B# }- e* ]' g/ k0 x7 {0 n这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。- x; J/ [& o& T- i
6 m- \4 J/ d% r5 T# U% b* @* S5 c百家乐的真实概率含义是:
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假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球 O! A; J% v" t, c o* W: z
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1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。- x9 h3 U5 X7 \1 G
& g: Y- {) z. a: X你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。
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你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。
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1 [' Z1 X; g' v6 ~7 X+ X' Z# F. s! l另外一个说法是,
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1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。# Q, U* f3 s" x$ e0 k( H
! F* R& M3 [; P2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。 l/ q/ t$ x9 F" [
( y# V9 y6 ^# D再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。
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平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。* ^: \* T7 {2 w7 `' [3 Z9 s
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对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。; h- d/ @/ _( ?3 ]+ p- z, c7 |
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举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。' }! E. \4 Y2 j5 Q" b
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第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化
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7 v8 ]- b/ V0 n* M! D. m第三,凯利公式的问题在于:形而上学。
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首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。
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事实上,你玩的时候,基本上每次都能打到。
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! N+ O5 H* }2 ~2 P8 E3 ?* L因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。7 e! ~' \ z3 F
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