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[lastpost] => 2765769 【星宝】9月15日投注流水4920元 1758246892 舞出精彩
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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
& P, u3 ?4 i- p# Z& T8 O5 d* J3 d5 `4 `! Q
假设大路开这样的路:, L, C9 Q2 H2 m d, a6 g
2 |' \. X8 W) Q2 E
12121212121212121212121212121212。
* |. I& R: @- N k) @
7 K+ \4 a" q( v0 E 按2珠路,就是BPBPBPBPBP。+ F3 O5 o& B- B1 z
+ Q, A- A3 Y) [1 t: g, o 如果我们去掉第一口,就会出现完全相反的结果:3 x1 Z6 h/ _7 N
/ F# F/ ^( C4 v8 F& Q4 R/ y4 F' H 21212121212121212121212121212121。* S! ^; e: }1 c/ [) z/ N
$ b: S) I& s. K7 o- q* @
变成了PBPBPBPBPB。
2 z0 [$ Y. x7 H: e5 S/ Y, K; l) q/ k3 Y% u/ y3 j: _: K
如果我们再去掉一口,又返回第一种情况了。# d2 B3 m4 i/ o& P2 }
' O, }5 t k, {8 m9 v/ v" Y& H
所以每一条大路,按2珠路排列,有2种不同的路数。
$ D r) E" x, L! a$ `! p+ L/ Q! W! q' c
再举一个列子:
" b/ O5 H( N) J5 B9 {2 Y0 `& }5 Q+ f8 U
1 \! K7 ~) U. p/ n 大路:122122122122122122。, v- u0 q5 k1 C. M/ m
( |5 I9 l; a% n6 i% b7 D; {! H" \ 按三珠路排列:' y" n$ v2 j9 m/ s: G2 D
3 q0 L1 m7 P) c3 D& k9 q
122,122,122,122,122,122。
" o7 D- g$ _# Q, F- e
4 E, T D1 s% ]7 U8 E) k ~" d; x 去掉第一口,变成:- Y& J% H1 Q" Q3 _5 y4 y# k* \' p
H) |0 `$ F8 c3 A! Q/ a& S 221,221,221,221,221,去掉前2口,变成:8 u3 m: k* y& B+ b% H( X5 t
/ _3 A9 O9 z. S$ l8 Y- v
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。& o6 I; V3 a1 o M
. l- @9 P7 n# R 同理:按N珠路排列,有N种不同的路数。! D) { ]1 c: @* x6 S/ j
" b# W H7 I/ t4 Y 我提出这个的意义在于:) b$ Z9 g. S9 _, g' E" Z1 |
! M% ~; J4 a, p% \4 L 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。6 f, |( S( b; r `! v b3 l
+ |0 C3 R+ s! ]* B 2、为三多理论提供了下注的多面性奠定基础。
& i0 c- \1 u$ x' N% K5 B+ l9 V
& d2 u' G3 L" W n) A+ k1 l( n 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
1 T6 G( s+ G5 }% U: i1 I" B f6 Q3 d m4 d5 d
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我现在还是研究一下理论打法,感谢你的分享,我也来学习 |
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