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[打法交流] 德州扑克手牌组合有多少种?(转载)
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1#
起手牌组合* P1 n1 e4 \4 L- I+ p
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德州扑克中可能的手牌组合数有C254=(54*53)/(2*1)=1326种特定的对子牌有C24=(4*3)/(2*1)=6种组合. _$ F2 ~+ V8 V( D# @% [2 s
特定的非对子牌有4*4=16种组合* Q' m  g) S1 \: H2 z  f
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特定的同花非对子牌有4*1=4种组合5 J! `" [& b2 \$ u' H

6 o0 L: _! t- ?+ a1 MAXs有13-1=12种组合! u" ~! n1 L, \! u
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KXs有13-2=11种组合: Z* {# j6 s1 \5 @

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思考:去牌效应的应用。
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+ a' j+ {$ ]! J6 z2 |HERO手上有一张A,那么对手AA的组合还有多少呢?- z4 t. f5 [; W" n. o. H( C- {

. b- A: }  ^3 J6 Y! h" Z答:有C23=(3*2)/(2*1)=3种,与你没有A时的情况相比少了一半。
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HERO手上有一张A,那么对手AK的组合还有多少呢?
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答:有3*4=12种,与你没有A时的情况相比少了1/4。
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手牌组合
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' v* A' c) ]8 i) e成牌组合
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FLOP没有公对时:+ A4 ]! F* \! ?% c. x+ y' ]

/ a9 }( G2 |: l2 T# H三条的组合有C23*C23=9种
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指定三条的组合有C23=3种( x6 K0 v: x: L* P

, ^) m( `, h1 W% v- y两对的组合有C23*C23*C23=27种
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$ S; N% k2 I4 R  N指定两对组合有C23*C23=9种- U5 k4 ^5 t! }; Z/ \6 s

  F! Y. L; a  l7 X3 BTPTK的组合有3*4=12种$ M3 P$ m; B. ]

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! T/ T7 j7 ?1 r' x/ AFlop有公对时:
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明三条顶踢脚的组合有2*4=8种% K- v4 v& J' g& t9 D; E" v

- z) ]# c- x8 T, p9 g葫芦的组合有C23+C13*C12=9种
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3 A1 B9 I& c: [$ P3 {听牌组合, k* q+ l; k3 [  @+ }. N7 u

% n# u' N% M& W2 V' IFLOP有两张同花时:. ^" t* m6 }/ _3 O; A4 G
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对手理论上的同花组合有C211=55种
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1 U- e- L: d/ ^' G! V1 `* q而当你手上有一张同花时,对手理论上的同花组合有C210=45种' m! y9 @. m( W+ l

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在类似K34这样的FLOP时:$ ]0 Y% C, f5 H; y# R) ~" O
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两头顺组合(25、56)有2*4*4=32种9 g, ~, p1 ^! j1 A+ s4 b
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卡顺组合有(A2、26、57)3*4*4=48种
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在类似K56这样的FLOP时:
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两头顺组合有(34、47、78)3*4*4=48种
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卡顺组合有(24、37、48、79)4*4*4=64种- }% g6 Z; w) y" d7 f

3 v. a+ R- J3 F, k思考:当你知道对手只玩同花连牌时,组合数会发生怎样的变化呢?(这个请大家自己做个计算吧~)6 {; g7 z3 M* w

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参与人数 1贡献值 +3 收起 理由
avatar 天策-瑶娥 + 3 理论区转载发帖奖励

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2#
这个组合应该是很多的了啊。
avatar
这个组合也是要看一下的了
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4#
知道有多少种,肯定是有好处的
avatar
5#
主题回复处广告图案-天策传媒
你的理论打法不错的呀,赢钱了应该是打法对你有用哦~来收藏下了解下了
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6#
感谢楼主的理论分享,也是可以了解到好多的。
avatar
理论实践得好,收米的时机就来了。
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你估计也是一个理论很内行的玩家,感激楼主的分享。
avatar
9#
老哥的理论打法也是有在记录中的呀?
avatar
10#
这个理论打法是需要向这个朋友多学习一下的。
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11#
基本理论也是要学学的了哦
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我的成果的功劳都是楼主像这样的理论分享。
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理论也许看着很牛逼,但是我还是不行
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这样的理论还是需要多多看看一下。
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这样的理论打法是十分科学好有道理哦,我也来收藏
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16#
老哥的理论打法还是很好啊,来收藏下了解下了
avatar
理论看看一下,肯定都是不会吃亏的。
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