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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O, F' a6 s% W( V
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发现了一个有趣的现象，
5 Q4 v% C5 ?+ C3 d, Q/ L6 Z每一条大路，% a. b. C3 G/ Q& o0 e/ o
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f, D# O6 k5 P8 r9 D) f' W
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z9 L9 _7 _# m' M1 }1 A0 I
按4珠路排列，有4种不同的路数2 w) p2 [3 r1 }7 P
按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C# r9 b# s) C/ q4 S u: ]7 t4 V' }
什么意思呢，可能大家一时不清楚，5 R* P, O0 c# d5 i6 i* q" ^" v7 `
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
- a5 _+ @8 Y1 D9 P" J# u, J% S假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u9 \- c8 a- J' I- d1 K/ X7 p Y
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h8 S' j* E- C% [8 m
够极端了吧) m. ^8 T# p3 R( y/ L+ {
按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F8 m0 W9 T2 q k L8 @5 v6 }- g4 G% e
如果我们去掉第一口，就会出现完全相反的结果：
# D: R \$ }" J/ [8 Q- Q9 J21212121212121212121212121212121
4 w1 k6 {6 D( w- Q变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C0 ?* p( ^, Z. _1 T; i5 K# {
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
7 S' {) v: T) Q+ H/ z8 O& b所以每一条大路，! R6 V# q$ h. c; z% O: i' `8 q. `; V: b a) F) M
按2珠路排列，有2种不同的路数。
4 U$ R% A( T9 ? v- ?再举一个列子：
3 C0 [9 C2 v+ ?0 ]2 |大路：122122122122122122。。。 _- j$ X: ?% @, u; J) o1 K
按三珠路排列：7 ^' j/ b: |: E0 q* ]
122，122，122，122，122，122。。。& R% s# w7 \& O% k7 `+ k
去掉第一口，变成：6 G2 V! \" L' c" k: d# j! \4 v) R: W# D; m$ n+ d
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
8 y+ y% i' q! Y/ T, G去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W, E% e4 N# W' j8 @, P* i2 l9 p& n
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `" ? W: {( m0 B2 h" q+ {1 P( r
去掉3口，又返回122，122，122，了
) a7 f5 V k) C( x" t所以每一条大路，
8 r2 r3 m; J% @" h, h按3珠路排列，有3种不同的路数。; x! Y# l: ?; h* s
同理：按N珠路排列，有N种不同的路数。; z$ [( Z Q8 B) g& q
我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O5 S: M: c& L/ g) ~/ s! D$ p
字串83 L: R) G1 V- s2 Y+ Y# j1 c- R+ b( \- A3 R P
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1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |, ]7 F: o4 r( O5 ^+ g
2、为三多理论提供了下注的多面性奠定基础。
) X3 ~ w0 L, g: n9 t3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.
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