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! x6 A- Z' c K
5 X7 J! ]* v2 N5 o通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
) h' z7 l! a5 V6 w+ ?, g C) J/ ], a) T. g
假设大路开这样的路:8 X6 s# z9 @( C( q. Q
. i9 g X J$ T5 f- G/ i8 |
12121212121212121212121212121212。 K5 @9 F( A2 P( A
/ ?/ V5 |* `) N$ T3 N w
按2珠路,就是BPBPBPBPBP。
. p2 Z: t3 l! ]6 @) h* W; y+ M, ~* S" g
如果我们去掉第一口,就会出现完全相反的结果:
8 B, z1 I; a, j0 H2 H. {
% |! I/ W9 C3 m# s# A% v 21212121212121212121212121212121。
+ J$ q% f% E! j
0 [. r/ g m, m, B. k 变成了PBPBPBPBPB。! V1 X" n2 @5 K/ W; o- j9 a
( _% k9 D% }- A, p# q% d. l
如果我们再去掉一口,又返回第一种情况了。
# Y% }: m8 R; c/ T7 X$ H
: f$ x9 e; ]# H 所以每一条大路,按2珠路排列,有2种不同的路数。* x ~- k7 D |8 e. L3 v& {
p$ D' ^/ d; o* X, D/ f* z
再举一个列子:) n6 d5 A q4 I4 e; H# q) ~
' ?7 W- c3 L8 e- l 大路:122122122122122122。
' L7 g9 K1 H. L! x. D2 s) Z$ a$ W9 F8 a
按三珠路排列:
9 G3 m" S, N& \) P- i
5 V- ~- g% t* S8 O! H3 Q+ [ 122,122,122,122,122,122。
; R; [- E) U" D8 q: b
9 i1 Y6 _/ g' ^- I. Q 去掉第一口,变成:: M$ q; w8 U1 B/ ?
. A# l2 ?. R' V' j* @ m( H1 T 221,221,221,221,221,去掉前2口,变成:
+ a! A6 _! `2 X7 D0 t4 y, V1 M% S4 s* _" C1 _2 @
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
* B3 ^7 H4 A0 Z9 c3 q
( h5 }+ S% z3 k3 Z 同理:按N珠路排列,有N种不同的路数。
; Z# ^: E; I! Y: D* V# F/ W, ^. l3 k: v
我提出这个的意义在于:
. ^3 Q$ v) g+ U5 N' R' @% I4 E; e! _. s6 w
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
% R) W& {: B5 {- V' C' J
1 u/ S3 t7 m# A5 k- N3 I 2、为三多理论提供了下注的多面性奠定基础。
+ c( p, f7 r' b& i$ q; Y( I: W0 h: w: q5 a5 b/ `9 J
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。( _1 V! ], B' X# y$ ?. D
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