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# _8 j' _% r! n& u ]9 `
: K5 O2 {# z9 S9 L& Y8 P2 [. u通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
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! ~4 O# I3 l+ P+ {$ z- m3 x: x, z 假设大路开这样的路:9 u8 W: e3 v. g$ g0 X: s
7 b) T8 l3 f% N8 I( C* K! `4 B4 v
12121212121212121212121212121212。) J: _7 G: U+ J% _
: b5 T3 d( ~5 R- \ b
按2珠路,就是BPBPBPBPBP。+ v: B7 j' o- y
0 Z7 k: n Q" x* K
如果我们去掉第一口,就会出现完全相反的结果:& s; T5 h4 p( V$ y
# V6 v+ i& Q2 e# P9 d( m
21212121212121212121212121212121。
$ @0 l, G/ O2 D/ j( j( V) G( j" c5 R& | J
变成了PBPBPBPBPB。
: Z/ W2 K. n9 _! Z, d$ D
0 C$ P7 @! k/ h 如果我们再去掉一口,又返回第一种情况了。. k( Z% e& }4 y. v8 B
# i+ Q, j5 k4 D# e
所以每一条大路,按2珠路排列,有2种不同的路数。
1 f: F# ?4 X. n8 z. f9 B: W [4 k, `$ d' O' y
再举一个列子:$ t. l5 b; e# ^3 I* M0 T3 `1 d
1 c1 [, ?! _: E/ [2 T& e 大路:122122122122122122。
/ C5 P( |# T9 x/ V4 a9 x9 L2 I
- M1 W. g3 h4 v0 ?- Z. { 按三珠路排列:
6 m. o$ C- `% n% k. \' v4 L1 h% A
122,122,122,122,122,122。5 s1 y+ ?. z& V! D2 [
^/ m l8 K8 [ 去掉第一口,变成:1 w2 B$ |; b3 j5 k7 Z& p5 s, h
2 a% _% f# _1 J' {* g' _# A% D; @) d8 E 221,221,221,221,221,去掉前2口,变成:2 }1 r' u" [& i6 s- Y6 x/ W
1 J) z) B) r0 \1 }% y
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。6 E% N1 l2 X6 j J+ e
E# a2 T: v) H& E
同理:按N珠路排列,有N种不同的路数。
& G1 g- b# ?) [# G4 ~' G! t- n2 {" A- _
我提出这个的意义在于:6 `0 V% L# M& ~* h
, E6 k0 u& P. d2 K, Q! z( @5 s
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
4 a# Z2 h8 G. s' \# A! R( k0 N* S2 {' Y; y+ Y
2、为三多理论提供了下注的多面性奠定基础。
9 s4 ]+ m' I; A) z& v3 z! K" R# L7 q$ X8 @5 c. k
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。/ v: ]; q2 P( \/ Q$ {
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