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[lastpost] => 2772337 【星宝】10月9日投注流水261642元 1760081248 rainwang
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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。) s0 Y1 B. {" q' Z# g4 Q
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假设大路开这样的路:; {5 m. v% `0 X: z/ a
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12121212121212121212121212121212。$ ]% |& S, ~& ~8 L4 R; |
; z* S: @4 p! b8 z9 y4 K$ H9 V 按2珠路,就是BPBPBPBPBP。
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5 |5 j, e! w/ i- w 如果我们去掉第一口,就会出现完全相反的结果:5 t, f( P3 d' `8 x# y
6 d* M* c- m5 P+ ]+ ?7 J
21212121212121212121212121212121。' h+ v& M" [( Q( C& j
0 Y% \0 o5 ?% f; U 变成了PBPBPBPBPB。
2 @" C5 E" G( n+ v' o3 r, q7 M, Z5 b/ g! v4 c6 T1 G5 w
如果我们再去掉一口,又返回第一种情况了。' \7 K- K/ V, M* q
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所以每一条大路,按2珠路排列,有2种不同的路数。, n' S( A T" L3 e% r$ {
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再举一个列子:# N. z* v* k& g# ^/ q
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大路:122122122122122122。
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按三珠路排列:$ P: O2 O5 }5 s4 \. Q
1 p! X, U/ W* Q A4 c$ E 122,122,122,122,122,122。6 m+ w+ n9 z: v4 s0 K/ }) x
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去掉第一口,变成:: S8 u: ?/ [! q
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221,221,221,221,221,去掉前2口,变成:
% e8 Y2 L8 l$ E; u3 h
2 M8 o0 L: \( r& L# M8 Z+ x 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
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! s+ |4 L+ m" f0 B- Y& F 同理:按N珠路排列,有N种不同的路数。 M7 l1 N8 v1 T0 e4 M- X" V4 E5 w
2 y/ L% r2 v& o% [5 x/ c- J 我提出这个的意义在于:
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1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 [% J3 f! I$ ?' U) Q
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2、为三多理论提供了下注的多面性奠定基础。
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( u0 {' j2 ~; t4 _. @ 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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