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4 D8 U4 e5 Z1 Y. O1 ` n; ]9 l9 T4 l6 C' G, E' P7 B# B( p
通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
* W5 U3 n% L1 [6 h, X7 ? o
! t& K+ T i8 E0 G2 p 假设大路开这样的路:8 ]. z" p. X, v& I7 e. C/ e. d
# T; T+ m. r' m' T+ C. S" a l- l 12121212121212121212121212121212。
- g, w2 C& b F# q3 z
3 ?& z' o8 H5 I( y3 Q. @7 r1 c 按2珠路,就是BPBPBPBPBP。" g v% S W9 K2 o& h
. ?+ Q7 @$ q: I$ Q) D- j6 s" l! G 如果我们去掉第一口,就会出现完全相反的结果:9 `$ J% T6 W; k3 G
0 U2 k2 e! \% k 21212121212121212121212121212121。
$ W) K4 X5 V" t0 D( Q* F$ k' J% t# ^5 G/ t" B/ _) c% }
变成了PBPBPBPBPB。
, C0 k1 t3 ]6 ]$ v5 d0 [2 J
7 W5 w4 g7 k7 g5 P 如果我们再去掉一口,又返回第一种情况了。6 D7 ~: h3 o5 E
# @3 f- Y/ N1 U/ k: M 所以每一条大路,按2珠路排列,有2种不同的路数。
) C* P( n9 O R( T
( X) J, F- e& ]' A! W c1 U 再举一个列子:, P7 N. f% C3 a0 f5 C' F( K
) ~: P- @. S$ ]$ I# q% S' U 大路:122122122122122122。
# C( l/ _- K3 ~: V; n( m1 @6 M x/ d2 X. o
按三珠路排列:
g; X) V. o/ q, k* e9 g" R% s: S W3 C! P) ]" E
122,122,122,122,122,122。
! G9 @3 ] M9 t
, A+ C( Q$ l' u/ h6 Z 去掉第一口,变成:% W9 N; T- Q& k6 X( c. x; B- R2 I: m$ S
! k: u& z# g6 V0 O
221,221,221,221,221,去掉前2口,变成:2 L2 ]; A9 ?7 q% H8 T
+ ]' v) z0 t( X0 T
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。( g+ t: b; B# B
8 F1 l+ z9 V' J
同理:按N珠路排列,有N种不同的路数。2 H! A4 h: D2 g7 t* @8 m, g
. b' x& x2 p- ~( T
我提出这个的意义在于:
! U% j' x+ w% V) e% v: t$ x) n" N: b! i
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 A, ]0 X+ n. N9 J
. Q! H% l7 d) z, Y
2、为三多理论提供了下注的多面性奠定基础。
$ k3 q3 N: [+ e9 E7 ^. i6 R* t
. ~8 K3 v# l4 n% ?8 f6 w 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。/ Y" y+ X+ F/ c
" N: t$ `. L3 U2 b {
1 s; A/ x, h: q4 u3 [
1 ^7 v' o5 r% w9 _" g; o
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