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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。3 C9 p. N9 R! ?) U( P
. w. f$ T; S" T& @$ X' Q/ M0 u9 m2 j 假设大路开这样的路:
' M6 z, m' ?3 y2 i4 q% s7 D% I" Z2 n
' E6 V, U( K4 ^, K 12121212121212121212121212121212。0 s2 g) ~- z9 `( A" E8 o
: U8 {% Z; l# z 按2珠路,就是BPBPBPBPBP。
- K+ _9 v0 m5 l+ i( L' \3 W1 Y' M+ L" f1 n, i6 [$ ?- }
如果我们去掉第一口,就会出现完全相反的结果:. F, T9 i3 R' j5 U0 J9 v
8 @5 G: _2 `& r1 G2 V% x# r$ S4 l: k
21212121212121212121212121212121。, a- Z+ l$ u# A+ K
5 \6 I1 I* U& S H 变成了PBPBPBPBPB。1 J9 N2 @3 s! k; R* Z; K
, [0 s0 V1 w: P6 ^
如果我们再去掉一口,又返回第一种情况了。
& n9 ~4 e6 Z0 c; O$ V% r4 i- D2 M; s8 `4 H) X- _! Q3 F. o
所以每一条大路,按2珠路排列,有2种不同的路数。
, P: @3 W% ]( D. e
& R; K* F7 s) k5 p8 G 再举一个列子:; y# N; \5 s" t; Y2 x9 Y t4 A, ~4 c
' M4 M5 {& t% j. ^3 E! {
大路:122122122122122122。; l r2 @& \2 ~; H6 I
8 K q! e6 I6 z% R1 j! a
按三珠路排列:; f, w* w) _3 W1 b& A" V/ j
' Q# I0 u6 p7 ~/ S4 M
122,122,122,122,122,122。/ K# j# x. H* v7 X, [" Q
) Z6 Z Y" N1 K) N9 h/ ?
去掉第一口,变成:
9 N6 Q4 P' C* N# C6 g8 f7 ^
4 Y% J" A7 E# @4 s) ]" O 221,221,221,221,221,去掉前2口,变成:) P) f- |, I* P y
8 l j1 P+ Q* w D. I/ H3 W 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。7 T* f. p8 C4 {( T! t8 q6 i) `
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同理:按N珠路排列,有N种不同的路数。( Z- V$ ^% d" z T: t3 u
" K1 H- V/ L3 c 我提出这个的意义在于:
) t2 e6 r, |+ d
+ b! f1 b5 w7 _) q/ V! N8 E) o 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。$ K8 \1 E* D% w2 ~& |. w
1 j. W" M: S0 v/ p7 T 2、为三多理论提供了下注的多面性奠定基础。6 x; Z+ o& F. j; l: ?4 S' d( i
# @ Q% Z G( U( a 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。 }5 ]2 N0 \' o1 X) G
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