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* @* |4 b# K; G0 C2 k3 r% J( F. Y/ i
通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
+ Z8 Z* X& e2 S" r/ W
% E, Q% L5 w% I0 L) G 假设大路开这样的路:
, R1 k6 Z& y" k4 {% D* z+ C4 Z7 f1 P6 T$ C
12121212121212121212121212121212。. H P& {/ V9 C$ w: r3 H
. T. W" ~2 l! @4 c; L6 m p2 m, M+ v
按2珠路,就是BPBPBPBPBP。
# P4 ~* u- h- Q
) f( ]9 o$ s h, d. ` 如果我们去掉第一口,就会出现完全相反的结果:: j: o& [2 { d3 b% ]1 N3 p+ h
, v$ I4 Q; ~6 k5 M" p" q 21212121212121212121212121212121。% B f, f$ E! A" @* F' O
1 t( Z1 Q( i1 W& j2 I* H8 _
变成了PBPBPBPBPB。6 J6 f2 C' e0 x- @
. A$ k n1 U! s+ p0 b/ r- o+ r+ ?
如果我们再去掉一口,又返回第一种情况了。
, Z( l2 ]; j! W( t$ Q! B8 H5 @! d$ s
4 q# M. W$ M6 Q8 D U, w 所以每一条大路,按2珠路排列,有2种不同的路数。& M I* ~9 f3 \, c6 }) ~9 Y
$ y+ ~" p4 t' _1 E( [. o 再举一个列子:
6 J4 Y- U% O) i$ \7 T1 ~2 ` s$ Y) z& M/ D4 Z4 B5 M2 u2 b- j
大路:122122122122122122。
/ A! G0 e9 l& I; d# J. z( s
. g! v9 }8 T* [& J: b% w# x. K 按三珠路排列:# g" S2 u3 A2 ]: _5 Q' d
: W8 j, n, p% {: B- R7 ~
122,122,122,122,122,122。
" N* a8 Q! a& M
; Z7 R A0 \0 Y7 B) K; t Q 去掉第一口,变成:
6 n) }& l+ i3 s
# c4 _3 z5 m+ l; @ 221,221,221,221,221,去掉前2口,变成:# G f6 {" e3 g4 d% M; Y& `
5 H3 I3 k Q, S; H+ I
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
7 H8 U# O/ O5 z$ ?7 T7 N
' `2 r$ ]3 ~3 Z5 ~# h7 d 同理:按N珠路排列,有N种不同的路数。( R* l A0 V$ ~% W* o
: s7 Z" |. R$ x 我提出这个的意义在于:
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, k/ j4 Z6 ]/ ?! k+ x, \( E) `5 Y 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
! }) m2 I: r. a4 ^+ Y; c' L6 |) F6 Q1 B. |6 ?! S/ E
2、为三多理论提供了下注的多面性奠定基础。
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# u# [' O2 f6 Z) I6 D/ U 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。- U, l+ N" {, r3 C2 n) Z; e" p
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