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$ [; V" A a4 E& E/ J: `
) Y% z ]/ @) M5 _通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
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/ s7 j( H, q$ c' k 假设大路开这样的路:
) I) q! F6 _5 s* e- Q2 d6 w% |/ ]: p. T: d$ Y0 ~! \, k
12121212121212121212121212121212。7 q" p7 e, U8 S# v, L2 J
7 |! S$ F! x. ?4 m1 G A8 }4 z 按2珠路,就是BPBPBPBPBP。8 p; C2 q# K7 _' J
7 o: j+ P& S/ W8 n 如果我们去掉第一口,就会出现完全相反的结果:
' U8 C6 ]9 i8 `1 o" i+ a( v8 o4 M+ A+ S' ]$ y
21212121212121212121212121212121。! @6 p; t7 _; r$ k
M& | S b3 ? 变成了PBPBPBPBPB。$ j' C$ k4 V( _) [- x0 Q
4 _6 W* D; z9 n) y6 P2 }, p+ @ X
如果我们再去掉一口,又返回第一种情况了。$ z; s! v6 i2 ~
7 K* `( J# |2 ]
所以每一条大路,按2珠路排列,有2种不同的路数。. i6 _6 Y+ o8 s8 E
! o% Q% V$ [1 t# l
再举一个列子:
4 C6 ]/ F/ ~, U/ Z$ Z a* O/ @4 h4 L; l0 u1 T9 F
大路:122122122122122122。3 U# T# F( u' n& X
+ f8 b5 @7 r% r% a 按三珠路排列:
9 q; x% h) k, R3 ~. }3 K" {% h. _. ?
122,122,122,122,122,122。
& y" e3 i) a( ^7 d9 s8 M( ~( n/ C( t8 W8 O" i
去掉第一口,变成:( D- Y) P8 r( f' L9 `* L5 h T
K% k0 s: @6 [2 ]0 E: m
221,221,221,221,221,去掉前2口,变成:
! R/ n% s) P0 w6 t0 [$ e: `% [8 ~& y
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
! w: F, s; ^0 ?) G( |8 @
& j* x% u, G. O5 _, P; _$ {6 M: C7 F 同理:按N珠路排列,有N种不同的路数。
, ]0 F3 ~& d3 _. {* U
" h& I' p" o! h! v 我提出这个的意义在于:
: I/ \/ I' b% v) Q0 l4 z2 b! d! [* v- |/ o9 |' y" Q4 |6 w" N
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
# O" Q( {/ V! A0 z+ ?8 A9 I/ ~! S% Z1 e/ G H8 c
2、为三多理论提供了下注的多面性奠定基础。3 O0 T0 _0 |; X, w- n9 I$ H8 \
7 F8 K3 ]. b- @2 h- Q# z8 S
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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