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[打法交流]
近期在网上研究到了个百家乐著名战术 蒙特卡洛战术
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百家乐蒙特卡洛战术，需要纸和笔。但是不很难。: m) Y' ~8 C4 f7 Y9 U
|4 K7 N% O/ w2 C* U; e0 \* V1 e(1) 首先写「 1 2 3 」的数列。
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, ~# i/ Q# ]9 R9 f) {+ q8 P(2) 赌本就是左端的数字 (1) 加右端的数字 (3) 即是 (4) 。; j, C. T; {7 K) } p A
; P3 ~- e3 d: i% r( I) @(3) 输了的话就在数列右端之外又加上顺序的下一个数，现在这个例子要加的数字 (=4) ->( 「 1 2 34 」 ) 。如此类推，并且重複上面的第 (2) 点 ( 但今次会是 (1)+(4)=5) 。9 ?3 n6 C7 e# K+ L/ c
5 G3 @ V6 |' J. \3 l(4) 胜了的话，倍率 2 倍的游戏就把左端的数字 (1) 和右端的数字 (3) 消去。倍率 3 倍的游戏从数列上去掉左端的二个数字和右端的二个数字。
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" H$ Z) q$ ?% X6 ?(5) 如果数列所有的数字都消了就代表结束。
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(6) 想继续的话，回到 (1) 。
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蒙特卡洛战术的问题，在于如果没有充分而源源不绝的赌金，就会出现途中被迫停止的可能。而且连败的话，亦有机会超越 Max Bet ( 赌注的上限额 ) 。9 {; f% c J4 C
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二合一战术" @: K4 j6 j$ }, q: J. s
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这个可说是蒙特卡洛战术的一种，是以 1 局取回 2 局所输的方法。方法简单。写下输了的金额，赌注就那个左端和右端的数字的共计金额。
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9 n. T/ @- d, n$ b1 l/ j$ b: g: y譬如，先写下「 1 」。所以第一局的赌注是 1 。如这局输了，右侧添写 1 ，成为「 1 1 」。那个下一局赌注将会是左端和右端的共和 =2 。$ z+ f6 r2 j, q9 R/ K# G6 [
& K8 |) `0 j- _1 N) A* u1 K+ u2 U反复这样做，如四连败，数列将成为「 1 1 2 3 」。因此下一赌注会是 4 ，而且胜了的话，消去左端和右端的数字，数列将成「 1 2 」，下一赌注就等于 1 和 2 的总数 3 。再胜的话，会变成？3 h! R2 }9 M. R- d2 _; f
& \9 v* G3 K" b5 s, d! y儘管结果是 2 胜 4 败，共计收支是一加一减等于零。
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' R8 v% v- i, E% r6 F& U C" c& B这方法我试了不咋地，你们可能可以?
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